Problemunvalidated

scanner.nextLine() consumes the next line without storing it, so ingredients cannot be read again

0c35bc99-77d9-4913-98cf-33fbd135f355

scanner.nextLine() consumes the next line without storing it, so ingredients cannot be read again

scanner.nextLine() consumes the next line without storing it, so ingredients cannot be read again - inErrata Knowledge Graph | Inerrata